- What is the equation of a circle centered at the origin?
- Which is the standard equation for a circle centered at the origin with radius?
- How do you find the radius?
- What is the equation of a circle centered about the origin with a radius of 6?
- What is the equation for a circle centered at the origin quizlet?
- What is the standard equation of a circle?
- How do you find the radius of a circle with the center?
- How do you find the polar equation of a circle?
- How do you graph a circle equation?
- What is the equation of a circle with center at the origin and a radius of 5?
- What is the center of a circle called?
- What is the origin of a circle?
- Which equation represents a circle with a center at 2 8 and a radius of 11?
- What is the equation of the circle with a radius of 4 and a center at?

## What is the equation of a circle centered at the origin?

The equation of a circle with center (h,k) and radius r is given by (x−h)2+(y−k)2=r2 .

For a circle centered at the origin, this becomes the more familiar equation x2+y2=r2 ..

## Which is the standard equation for a circle centered at the origin with radius?

From this lesson, you know that the equation of a circle that is centered at the origin is \begin{align*}x^2+y^2=r^2\end{align*}, where \begin{align*}r\end{align*} is the radius and \begin{align*}(x, y)\end{align*} is any point on the circle.

## How do you find the radius?

radius is always half the length of its diameter. For example, if the diameter is 4 cm, the radius equals 4 cm ÷ 2 = 2 cm.

## What is the equation of a circle centered about the origin with a radius of 6?

So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.

## What is the equation for a circle centered at the origin quizlet?

In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation of a circle, x2 + y2 = r2.

## What is the standard equation of a circle?

We know that the general equation for a circle is ( x – h )^2 + ( y – k )^2 = r^2, where ( h, k ) is the center and r is the radius. So add 21 to both sides to get the constant term to the righthand side of the equation. Then complete the square for the y terms.

## How do you find the radius of a circle with the center?

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”.

## How do you find the polar equation of a circle?

The general polar equation of a circle of radius ρ centered at (r0,θ0) is r2−2rr0cos(θ−θ0)+r20=ρ2.

## How do you graph a circle equation?

Center away from the originLocate the center of the circle from the equation (h, v). Place the center of the circle at (3, –1).Calculate the radius by solving for r.Plot the radius points on the coordinate plane. … Connect the dots to the graph of the circle with a round, smooth curve.

## What is the equation of a circle with center at the origin and a radius of 5?

The standard form of a circle is given below: (x – h)2 + (y – k)2 = r2, where the center is located at (h, k) and r is the length of the radius. In this case, h will be –3, k will be 6, and r will be 5.

## What is the center of a circle called?

A circle is a set of all points in a plane that are all an equal distance from a single point, the center. The distance from a circle’s center to a point on the circle is called the radius of the circle. … A line segment that crosses the circle by passing through the center of the circle is called the diameter.

## What is the origin of a circle?

Definition: A circle is a simple shape, consisting of those points in a plane that are a given distance from a given point – the centre. Origin: the center of a circle. Radius: the distance from the center of a circle to any point on it.

## Which equation represents a circle with a center at 2 8 and a radius of 11?

(x + 2)² + (y – 8)² = 11.

## What is the equation of the circle with a radius of 4 and a center at?

The definition of the circle is “all the point with a fixed distance from the center”. You have to translate this in a formula. d=√(x1−x2)2+(y1−y2)2 . 4=√(−2−x2)2+(3−y2)2 .